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Compound Inequalities MEDAL!
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4x - 1 > 11 or 4x - 1 \(\le\) 11
@Nnesha
Find the interval notation and set-builder notation.
Would the interval notation be \((3, \infty)\) \(\cup\) \([\infty, 3]\)
(3, inf) is possible, but (inf, 3] is definitely not. In such interval notation, the smaller limit always comes first. Try again.
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I could give you more meaningful feedback if you'd show all work you've done.
sorry i meant (negative infinity, 3)
4x - 1 > 11 4x > 12 x > 3 4x - 1 \(\le\) 11 4x \(\le\) 12 x \(\le\) 3
We typically move from left to right on the number line. With that in mind, which of these two intervals comes first?
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