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Mathematics 19 Online
OpenStudy (yanasidlinskiy):

Statistics please? Check my answers.

OpenStudy (yanasidlinskiy):

OpenStudy (yanasidlinskiy):

If they're wrong, I'd like an explanation and a step by step walk through so I could understand it better.

OpenStudy (uri):

can i

OpenStudy (yanasidlinskiy):

What?

OpenStudy (kropot72):

You need to check your calculation for (a). What was you total for the number of participants in the study?

OpenStudy (kropot72):

your total*

OpenStudy (denonakavro):

Your first answer should be the coulmn of died from cancer divided by the total YOur second answer should be the row of current cigar smoker divided by the total Your third answer should be 165 (the intersection of the previous) divided by the total Your last answer should be the addition of the died of cancer column with current smoker column divided by the total

OpenStudy (yanasidlinskiy):

Well the total for dying of cancer is 559....

OpenStudy (yanasidlinskiy):

Unless, it's the last number to the right of the first column

OpenStudy (denonakavro):

The total is all the values added in the whole table

OpenStudy (kropot72):

The total who died from cancer is: 559 + 50 + 165

OpenStudy (yanasidlinskiy):

I know that.

OpenStudy (yanasidlinskiy):

For part A, I did: 559/133706 Is that right?

OpenStudy (kropot72):

Total who died from cancer = 774 Total participants = 133706

OpenStudy (yanasidlinskiy):

Ok, I see what I did wrong. Is B right?

OpenStudy (kropot72):

\[\large P(died\ from\ cancer)=\frac{774}{133706}\]

OpenStudy (yanasidlinskiy):

I know how to solve it, I just didn't know if I did it right.

OpenStudy (kropot72):

There are 165 current cigar smokers. Divide by the total number in the study.

OpenStudy (yanasidlinskiy):

For part B?

OpenStudy (kropot72):

\[\large P(current\ cigar\ smoker)=\frac{165}{133706}\]

OpenStudy (yanasidlinskiy):

So Part c would come out as the same answer for part B right?

OpenStudy (james1107):

yes

OpenStudy (kropot72):

"So Part c would come out as the same answer for part B right?" Correct.

OpenStudy (yanasidlinskiy):

Ok. So part D would be adding up B AND C right?

OpenStudy (anonymous):

No direct answers

OpenStudy (yanasidlinskiy):

@M*A*S*H I already know how this stuff. It's not a direct answer.

OpenStudy (kropot72):

For part (c) you need to use: \[\large P(A\cup B)=P(A)+P(B)-P(A\cap B)\]

OpenStudy (anonymous):

I was talking to denon

OpenStudy (yanasidlinskiy):

That confuses me. I do not know how to use that formula

OpenStudy (kropot72):

(d) In this case the intersection of the probability of (a) and the probability of (c) is so small that it can be ignored. Therefore you just need to add the probability found for (a) to the probability found for (c).

OpenStudy (kropot72):

What are your results for (a) and for (c) now?

OpenStudy (yanasidlinskiy):

Well for A I have: .005 And for C, I have: .001

OpenStudy (kropot72):

I agree with your answer for (c). However you appear to have not rounded the calculation for (a) correctly.

OpenStudy (kropot72):

What is the result for (a) on your calculator before rounding?

OpenStudy (yanasidlinskiy):

Sorry, .006

OpenStudy (kropot72):

Correct!

OpenStudy (kropot72):

So your result for (d) is.........

OpenStudy (yanasidlinskiy):

.007

OpenStudy (kropot72):

Wait, the question, as posted, does not state to round to 3 decimal places for (d). Does the original state this or not?

OpenStudy (yanasidlinskiy):

Yes, i accidentally cut it out. But yes. I have to round to 3 decimals as well.

OpenStudy (kropot72):

Cool. Then your result for (d) is correct.

OpenStudy (yanasidlinskiy):

Thank you. Could you check one more question for me please?

OpenStudy (kropot72):

You're welcome :). Sorry, I must log out now. Please post as a new question. Thanks.

OpenStudy (yanasidlinskiy):

Ok.

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