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The first quartile of a data set is 52, and the third quartile is 72. Which of these values in the data set is an outlier? A. 101 B. 41 C. 21 D. 81
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@wio @mathmale
@thushananth01
hello wio
Hi
can u help
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Well, the middle (2nd quartile) is going to be: \[ \frac{52+72}{2} = \frac{124}{2} = 62 \]So which number if furthest away from \(62\)?
what is all this [/{}/] stuff
i dont understand
but A?
hello
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@Photon336
No, 101 is not the furthest away
wut do u mean furthest away
21 is the furthest away from the middle
ohhhh
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so C?
im still kinda confused. can u help with another
I think it is C
It's the best candidate, being furthest away
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