Question

a: what is the length of the hypotenuse of triangle ABC?
b: find the length of the shorter leg of triangle ABC using two different methods. Show your work for both.

Answer 1

a) given

Answer 2

Can you explain :)

Answer 3

b) shorter leg will be the opposite side
so.. hmhmm recall your SOH CAH TOA
\(sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\)

which of the identities, has ONLY
the angle
the opposite side
and the hypotenuse?

Answer 4

oh so i use a^2+b^2=c2 or is 15' the actual answer

Answer 5

well, if you had the adjacent side, you could use the pythagorean theorem yes
but it is given in this case, 15 feet from what I can tell

Answer 6

well, if you had the adjacent and opposite that is =)

Answer 7

I'm sorry, I don't understand