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Anyone smart enough for this? ;)(;
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@zepdrix
Hi hartnn :)
\(\Huge \dfrac{x^n}{x^m} = x^{n-m}\)
It's square root, not to the power of......
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Didn't you see that?
\(\Large \sqrt[3] x = x^{\dfrac{1}{3}}\)
k
\(\Large \sqrt[4] x = x^{\dfrac{1}{4}}\)
So the answer is B. ;)(;
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yes, B is correct :)
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