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Solve the following equation for x.
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\[(3x + 5)^{-4}=64\]
So: \[3x + 5 = \pm { \sqrt[-4]{64} } \]
first try using x^(-1) = 1/x
this above wrote is right for exponent positive of 4 but there is -4
So you get: \[\ 3x = -5 \pm \frac{ 1 }{ \sqrt[4]{64} } \]
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Not exactly sure this part is right: (divided each side by 3) \[x = -\frac{5 }{ 3 } \pm \frac{ 1 }{ 3\sqrt[4]{64} }\]
I figured it out. It was how the book simplified the answer. Thanks all the same!
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