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Mathematics 17 Online
OpenStudy (18jonea):

Evaluate the series https://api.agilixbuzz.com/Resz/~Ey6YBAAAAAgdoo74Oe2HXA.oFBhsaZL8kW6bOnptzP50A/19809088,B84/Assets/assessmentimages/45218.jpg

hartnn (hartnn):

know the formula?

OpenStudy (18jonea):

No i dont

hartnn (hartnn):

\(\Large S_n = a_1\dfrac{1-r^n}{1-r}\)

hartnn (hartnn):

a1 is the first term

hartnn (hartnn):

r is the common ratio n = number of terms

OpenStudy (18jonea):

is there 7 terms?

hartnn (hartnn):

yes

hartnn (hartnn):

1st term, put n = 1 so 1/4

hartnn (hartnn):

common ratio = r =1/4

OpenStudy (18jonea):

1/1/4n

OpenStudy (18jonea):

divided by 1-1/4

hartnn (hartnn):

\(\Large S_7 = a_1\dfrac{1-r^7}{1-r} = \dfrac{1}{4} \times \dfrac{1-(1/4)^7}{1-1/4}\) just plugged in values

OpenStudy (18jonea):

so how would you find the answer?

hartnn (hartnn):

use calculator if they want answer in decimal, otherwise after some simplifications we have \(\dfrac{1-1/4^7}{3}\)

OpenStudy (18jonea):

they want it in a frction

hartnn (hartnn):

\(\dfrac{4^7-1}{3\times 4^7}\)

hartnn (hartnn):

4^7 = 16384

hartnn (hartnn):

\(\dfrac{16383}{49152}\)

OpenStudy (18jonea):

is that the answer

hartnn (hartnn):

yeah :/

OpenStudy (18jonea):

@hartnn

hartnn (hartnn):

16383/49152 = 5461/16384

hartnn (hartnn):

option C

OpenStudy (18jonea):

Thank you so much I have 4 more could you help me with them

OpenStudy (18jonea):

@hartnn

hartnn (hartnn):

its past midnight here...i may go offline soonn

OpenStudy (18jonea):

ok

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