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3 sqrt 2x+6=18
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sqrt2x or sqrt(2x+6) how is exactly ?
is it \[3\sqrt{2x + 16} = 18\] if so then first of all divide by 3 on both sides....
u mean only its only the sqrt of 2x ??? then u need to eliminate 6 from the variable side...so subtract 6 on both sides of equality sign
no its the sqrt of 2x+6 :P
ok. than divide both sides by 3
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ok then u need to divide by 3 on both sides
hint: if I diviby three, I get: \[\Large \frac{{3\sqrt {2x + 6} }}{3} = \frac{{18}}{3}\] please simplify
oops.. I meant ...if I divide both sides by three...
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