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If f(x) = 3x^10 -7x^8+5x^6-21x^3+3x^3-7 then Lim f(1-a)-f(1)/a^3+3a When a tends to 0 is
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I want to know if we can do it some other way except for L' hospitals rule.. Bcoz it is becuming very perplexing..
3x^2 in the question
After 21x^3 term
You can use definition of derivative Recall: \[\lim_{h \rightarrow 0}\frac{f(x+h)-f(x)}{h}=f'(x) \\ \text{ if we let } h=-a \\ \text{ then it looks like } \\ \lim_{a \rightarrow 0}\frac{f(x-a)-f(x)}{-a}=f'(x) \\\]
\[\lim_{a \rightarrow 0} \frac{f(1-h)-f(1)}{a(a^2+3)}=-\lim_{a \rightarrow 0} \frac{f(1-h)-f(1)}{-a} \cdot \lim_{a \rightarrow 0} \frac{1}{a^2+3}\]
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I have said too much now :p
but please let me know if you need assistance
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