Question

3. What are the solutions of the system?
y = x + 5
y = x^2 - x + 2

4. What are the solutions of the system?
y = x^2 - 2x - 8
y = x + 2

Answer 1

Since both are already in y =, set them equal to each other and solve for X. What do you get as your X for the first one?

Answer 2

i'm not sure, i'm pretty terrible at math

Answer 3

Alright, lets set them equal

X + 5 = X^2 - X + 2

When solving X, you wanna do the opposite operations until you get X by itself. So on the left, we have a positive 5. Since we do opposites, we would subtract 5 on both sides

Answer 4

i forgot to put up choices
3. What are the solutions of the system?
y = x + 5
y = x^2 - x + 2

A. (3,14) and (-1,0)
B. (3,8) and (-1,4)
C. (3,8) and (-1,0)
D. (-3,2) and (1,6)

4. What are the solutions of the system?
y = x^2 - 2x - 8
y = x + 2

A. (5,7) and (-2,0)
B. (5,3) and (-2,4)
C. (-5,-3) and (2,4)
D. (5,3) and (2-4)

Answer 5

so both of these systems (number 3) are equal to y, meaning that they are equal to one another
ex: 4+5=y
3+6=y
4+5=3+6
they both equal 9
in the same sense you equal both of these equations to one another
y = x + 5
y = x^2 - x + 2
will be
x + 5=x^2 - x + 2
from here solve
(tell me what you get and i will confirm)

Answer 6

and this process is used to answer number 4 as well

Answer 7

it has to be a solution like (0,0) i think i need a graph

Answer 8

ok so after you set them equal to each other you will get the answer for x which you will simply have to plug back into the system and get y
so your first answer will be the x and then plug in to get y
(x,y)

Answer 9

Is this Algebra 2?

Answer 10

no its algebra 1