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starting from any natural number if n is even you divede it by 2(you get n/2) if it's odd you myltiply it by 3 and add 1 (you get 3n+1).prove that you always reach 1
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counterexample if n=5 then 3n+1=16 and 16 is not 1
no
16 is even so you divede it by 2 and so on until you reach 1
you get 8,4,2, 1
you repeat the process
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oh I that didn't translate to me that we were suppose to repeat anything
oh i',m sorry guys..this is one of the unsolved problems..i just found out
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