Question

starting from any natural number if n is even you divede it by 2(you get n/2) if it's odd you myltiply it by 3 and add 1 (you get 3n+1).prove that you always reach 1

Answer 1

counterexample
if n=5 then 3n+1=16 and 16 is not 1

Answer 2

no

Answer 3

16 is even so you divede it by 2 and so on until you reach 1

Answer 4

you get 8,4,2, 1

Answer 5

you repeat the process

Answer 6

oh I that didn't translate to me that we were suppose to repeat anything

Answer 7

oh i',m sorry guys..this is one of the unsolved problems..i just found out