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OpenStudy (lisa2345):
OpenStudy (unklerhaukus):
The surface area of a right cylinder is composed of its two circular bases, and the lateral surface area. The lateral surface is a rectangle.
OpenStudy (unklerhaukus):
The area of a circle (or radius \(r\)) is \(\pi r^2\),
The area of a rectangle (of height \(h\), and width \(w\)) is \(hw\).
The width of the rectangle, is the circumference of a circle.
The circumference of a circle is \(2\pi r\).
OpenStudy (unklerhaukus):
Can you find the area of one of the bases first?
OpenStudy (lisa2345):
2*3.14*15^2
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OpenStudy (unklerhaukus):
There is no `2*`, in the area of a circle
OpenStudy (lisa2345):
the way I was just taught was 2*pi*r^2 + 2*pi*r*h
OpenStudy (unklerhaukus):
oh. then you have found the are of both bases at once.
each of the circular bases has the area πr^2, and there are two
OpenStudy (unklerhaukus):
If you already have
SA = 2*pi*r^2 + 2*pi*r*h
i guess you can just use it.
OpenStudy (unklerhaukus):
what do you get for the lateral surface area
w h = 2πr h = ?
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