Question

PLEASE HELP :( WILL MEDAL


Select the equation in which the graph of the line has a negative slope, and the y-intercept equals 4/3

5x + 3y = 4


5x - 3y = –4


4x + 16y = –20


6x + 2y = –8



Select the equation that contains the point (4, -8), and in which the graph of the line has a positive slope.



y – 8 = –4(x + 4)


y – 8 = 4(x + 4)


y + 8 = +4(x – 4)


y + 8 = –4(x – 4)

Answer 1

Okay well first you have to put the equations into slope-intercept form

Answer 2

Okay

Answer 3

@perii224, then plug in the numbers

Answer 4

Okay, do you know how?

Answer 5

Yes I'm in 8th, but I can help one second

Answer 6

Okay so subtract 5x from both sides

Answer 7

Okay, thanks :)

Answer 8

so it becomes 3y = -5x + 4

Answer 9

Oh okay, but that's not one of the options

Answer 10

Then that one is not it. Move on the next one.

Answer 11

So you dont know what the first one is?

Answer 12

the first one does have a negative slope, but does 4 = 4/3?

Answer 13

I guess

Answer 14

No it doesn't

Answer 15

oh

Answer 16

So next one...what grade are you in?

Answer 17

I'm in 9th

Answer 18

oh okay....Hmmmm did you learn point-slope, and slope-intercept forms last year?

Answer 19

I dont remember xD

Answer 20

oh okay

Answer 21

Do you know the second one?

Answer 22

one sec

Answer 23

ok

Answer 24

Okay so you have 5x - 3y = -4

subtract 5x from both sides

-3y = -5x - 4

can't have a negative 3 so divide both sides by -3 to get y by itself

y = 4/3 x - 4

Answer 25

Oh okay

Answer 26

does that fit the description?

Answer 27

I guess, but what is the final answer?

Answer 28

No it doesn't. keep doing that for all of the problems

Answer 29

Oh okay

Answer 30

is this starting to make sense?

Answer 31

I guess

Answer 32

that's not assuring