Question

1. What number would you have to add to both sides to complete the Square?

X^2-16x=-8
A.-16
B.16
C.64
D.-64

2. Solve by using the perfect squares method
X^2-12x+36=0
A. -18
B. 18
C. -6
D. 6

Answer 1

divide the coefficiebt of x by 2 . In this cast the coefficient is -16
than write it as ( x - a)^2 - c so that this equals x^2 - 16x

Answer 2

So #1 is B!?

Answer 3

no
what is -16 / 2 ?

Answer 4

-8

Answer 5

- this will give yiu the value of a in (x + a)^2

Answer 6

right so we have
(x - 8)^2 + b

now (x - 8)^2 = x^2 - 16x + 64
so get the left side = x^2 - 16x we have to add - 64

Answer 7

and we have to add -64 to both sides

Answer 8

Ok

Answer 9

for number 2 if you factor the trinomial you'll find its a perfect square
so you'll get ( x - a)^2 = 0

Answer 10

and the root will be x = a

Answer 11

youll need to use one of the square roots of 36

Answer 12

6

Answer 13

thats one of the square roots - but you need the other one because the middle term is -12x

Answer 14

Oh okay so -6 then?

Answer 15

yes
so it factors to (x - 6)^2 = 0

so what is the value of x?

Answer 16

x - 6 must be equal to 0, right?

Answer 17

Yeah

Answer 18

so what does x =?

Answer 19

x - 6 = 0
so x = ?

what have you got to take 6 from to get 0?

Answer 20

6

Answer 21

exactly so thats the answer x = 6

Answer 22

Thanks so much! I'm super bad at math, so teaching just require Patience lol. Thanks. So #1 is C and #2 is d. Correct?

Answer 23

Must*

Answer 24

It was correct. Thanks