solve each equation and show all work 1. 5x+7=3x+21 2. 3x-2(5-x)=3(x-10)+3 3. 5(x+1)=3(2x+3)+5
Line up everything that matches. like variables.
So for #1 5x+7=3x+21 so what would you do?
subtract 3x from both sides?
Correct!
Correct you want to get rid of one of the x's. So you would get 2x+7=21 What do you do next?
subtract 7 from both sides
Subtract 7 from both sides you get 14 so it would be 2x=14 divide both sides by 2 and you get x=7! Now do the rest :)
Hint: parentheses first always remember that.
how would i start the ones in the parentheses
3x-2(5-x)=3(x-10)+3 Distribute. -2times 5 and -2 times x you would also do 3 times x and 3 times -10 your equation should be 3x-10-2x=3x-30+3
so do you get rid of the 3x first
No the -2x so add 2x to the first 3x you get 5x-10=3x-30+3 then subtract 3x so you get 2x-10=-30+3 Subtract 3 you get 2x-13+-30 add 30 you get 2x=20 divide by 2 you get x=10 :)
#3 answer is -9
how did you get -9
which one are you doing rn?
@kiki345
# 3
alright
\( 5(x+1)=3(2x+3)+5\) open the brackets \(5(x)+5(1)=3(2x)+3(3)+5\) \(5x+5=6x+9+5\) \(-1x=9\) \(x=-9\)
thank you @ILovePuppiesLol
I can
-2(6-2x)=4(-3+x)
−2(6−2x)=4(−3+x) Step 1: Simplify both sides of the equation. −2(6−2x)=4(−3+x) Simplify: (Show steps) 4x−12=4x−12 Step 2: Subtract 4x from both sides. 4x−12−4x=4x−12−4x −12=−12 Step 3: Add 12 to both sides. −12+12=−12+12 0=0
thank you and i have one more 5-1(2x+3)=-2(4+x)
5−1(2x+3)=−2(4+x) Step 1: Simplify both sides of the equation. 5−1(2x+3)=−2(4+x) Simplify: (Show steps) −2x+2=−2x−8 Step 2: Add 2x to both sides. −2x+2+2x=−2x−8+2x 2=−8 Step 3: Subtract 2 from both sides. 2−2=−8−2 0=−10
thanks
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