A square painting is surrounded by a frame. The outside edges of the frame are x inches in length and there is a 4-inch border between the painting and the frame. What is the total area of the border?

Question

A square painting is surrounded by a frame.  The outside edges of the frame are x inches in length and there is a 4-inch border between the painting and the frame.  What is the total area of the border?

anonymous · Answer

so, could you guys solve this?

faiqraees · Answer

The answer should come in terms of x right?

anonymous · Answer

–16x – 64 
  –8x + 16 
  16x – 64 
  x2 + 16x + 64

faiqraees · Answer

Area of border = Total area - Area of Painting 
Area of border = x^2- (x-8)^2
Now expand it and you've your area.
If you want to know how i got (x-8)^2, let me know

anonymous · Answer

that's not one of the possible answers

anonymous · Answer

–16x – 64 
  –8x + 16 
  16x – 64 
  x2 + 16x + 64

faiqraees · Answer

I know I haven't given you the answers, Expand the brackets and then simplify the equation and you will have your answer

anonymous · Answer

16x - 64?

anonymous · Answer

Can we see a diagram?

faiqraees · Answer

Yep correct

anonymous · Answer

@FaiqRaees 
Could you explain how you got the answer?

faiqraees · Answer

Area of border = Total area - Area of Painting 
Area of border = x^2- (x-8)^2
Area of border = x^2- (x^2 -16x+64)
Area of border = x^2- x^2 +16x-64
Area of border = 16x-64