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Mathematics 21 Online
OpenStudy (wintersuntime):

Can someone be nice enough to help me please

OpenStudy (ihelpyoulearn):

Your question? :)

Nnesha (nnesha):

your username is perfect for this post :)

OpenStudy (wintersuntime):

A small meteor crashes down behind Chula Vista High School. A few students recover a 1200 mg sample of space rock. They discover that the space rock has a 1/2 life of 1 day.

OpenStudy (wintersuntime):

Complete the table

OpenStudy (danjs):

add a day 0 to that , when they discovered it at time 0, it was 1200 mg mass

OpenStudy (wintersuntime):

I was trying to fix it

OpenStudy (wintersuntime):

|dw:1456979528463:dw|

OpenStudy (wintersuntime):

@happytalesrebornn

OpenStudy (happytalesrebornn):

@BruhObamaCare

OpenStudy (wintersuntime):

I know that its geometric function

OpenStudy (danjs):

The graph is mass vs time points (t,m)

OpenStudy (happytalesrebornn):

Alright this is actually quite intriguing... you're the first person I've seen in a while having a go at attempting to solve for P versus NP. From what team are you working with? MIT? Stanford? I must come in contact with your department head IMMEDIATELY. I have critical information regarding your research.

OpenStudy (danjs):

Each 1 day, the mass is halved, if t is in days, then each time t increases by 1, the mass is multiplied by 1/2 mass at time t = initial amount * (1/2)^t

OpenStudy (wintersuntime):

am I suppose to multiply by 1/2 each time ?

OpenStudy (wintersuntime):

At day 0 would it be 1200 ?

OpenStudy (danjs):

each time a day passes and t goes up by 1 day

OpenStudy (happytalesrebornn):

What you might want to do is solve for every single eigenvalue independently via hilbert space utilizing a time-dependent constant then reintegrate everything back into several high functioning diffy-qs. I have some notes preped for you if you'd like

OpenStudy (wintersuntime):

On day 1 would it be 600

OpenStudy (wintersuntime):

Is it correct that on day 1 its 600

OpenStudy (wintersuntime):

Or is that wrong ?

OpenStudy (happytalesrebornn):

Honestly... I'm more interested in the money. Is your department willing to trade equity in the project for my notes?

OpenStudy (happytalesrebornn):

Please tell your department head to contact my main office: 1142-KAPPACHINO

OpenStudy (wintersuntime):

Need help !

OpenStudy (wintersuntime):

Wait I think I got it !!!

OpenStudy (happytalesrebornn):

DEAR LORD DID YOU SOLVE IT? HOW DID... OMG

OpenStudy (wintersuntime):

I'm so proud of myself

OpenStudy (happytalesrebornn):

HOW DID YOU ACCOUNT FOR THE THOUSANDS OF UNDEFINED GRADIANTS. WHAT ALGORITHM DID YOU USE TO DETERMINE THE RELATIONSHIP BETWEEN THE POLARITY SEQUENCING. WHAT A DAY. CONTACT NOBEL PRIZES

OpenStudy (anonymous):

o.O

OpenStudy (wintersuntime):

I hope I get an A+ for my quiz tomorrow

OpenStudy (happytalesrebornn):

You shall my dear padawan. You shall.

OpenStudy (danjs):

half life is a exponential graph y = A*b^x m(t) = A*b^t time t=0. ,mass m=1200 m(0)=A*b^0 = A = 1200 m(t)=1200*b^t

OpenStudy (danjs):

when t=1 you have half mass original (1,600) m(1) = 600 = 1200*b^1 b=1/2

OpenStudy (wintersuntime):

Explicit formula : f(x)= 1200 (1/2)*

OpenStudy (danjs):

general m(t)=1200*(1/2)^t

OpenStudy (danjs):

use that for the values

OpenStudy (wintersuntime):

Recursive formula : f(x) = f(x-1) * 1/2

OpenStudy (wintersuntime):

Thank you so much everyone for your help

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