Can someone be nice enough to help me please
Your question? :)
your username is perfect for this post :)
A small meteor crashes down behind Chula Vista High School. A few students recover a 1200 mg sample of space rock. They discover that the space rock has a 1/2 life of 1 day.
Complete the table
add a day 0 to that , when they discovered it at time 0, it was 1200 mg mass
I was trying to fix it
|dw:1456979528463:dw|
@happytalesrebornn
@BruhObamaCare
I know that its geometric function
The graph is mass vs time points (t,m)
Alright this is actually quite intriguing... you're the first person I've seen in a while having a go at attempting to solve for P versus NP. From what team are you working with? MIT? Stanford? I must come in contact with your department head IMMEDIATELY. I have critical information regarding your research.
Each 1 day, the mass is halved, if t is in days, then each time t increases by 1, the mass is multiplied by 1/2 mass at time t = initial amount * (1/2)^t
am I suppose to multiply by 1/2 each time ?
At day 0 would it be 1200 ?
each time a day passes and t goes up by 1 day
What you might want to do is solve for every single eigenvalue independently via hilbert space utilizing a time-dependent constant then reintegrate everything back into several high functioning diffy-qs. I have some notes preped for you if you'd like
On day 1 would it be 600
Is it correct that on day 1 its 600
Or is that wrong ?
Honestly... I'm more interested in the money. Is your department willing to trade equity in the project for my notes?
Please tell your department head to contact my main office: 1142-KAPPACHINO
Need help !
Wait I think I got it !!!
DEAR LORD DID YOU SOLVE IT? HOW DID... OMG
I'm so proud of myself
HOW DID YOU ACCOUNT FOR THE THOUSANDS OF UNDEFINED GRADIANTS. WHAT ALGORITHM DID YOU USE TO DETERMINE THE RELATIONSHIP BETWEEN THE POLARITY SEQUENCING. WHAT A DAY. CONTACT NOBEL PRIZES
o.O
I hope I get an A+ for my quiz tomorrow
You shall my dear padawan. You shall.
half life is a exponential graph y = A*b^x m(t) = A*b^t time t=0. ,mass m=1200 m(0)=A*b^0 = A = 1200 m(t)=1200*b^t
when t=1 you have half mass original (1,600) m(1) = 600 = 1200*b^1 b=1/2
Explicit formula : f(x)= 1200 (1/2)*
general m(t)=1200*(1/2)^t
use that for the values
Recursive formula : f(x) = f(x-1) * 1/2
Thank you so much everyone for your help
Join our real-time social learning platform and learn together with your friends!