Question

http://prntscr.com/aak2rn
I'm stuck on why. I found x. X is 9/4, but I can't find y even though I'm using the same process 2.25+4/y=y/4. What am I doing wrong?

Answer 1

In triangle ABC, By Pythagoras theorem
\[(5)^2+(y)^2=(4+x)^2...1\]
In triangle BDC Again applying Pythagoras theorem
\[(3)^2+(x)^2=(y)^2...2\]Putting equation 2 in equation 1

\[5^2+9+x^2=(4+x)^2\]
solve for x & then put the value of x in equation 2 to get y .

Answer 2

We actually haven't learned that yet. We're supposed to be able to solve this just by using proportions alone. The Pythagorean theorem comes later in the course.

Answer 3

We're using this http://prntscr.com/aak7n4 and this http://prntscr.com/aak7ui

Answer 4

I solved for x using corollary 2, and I'm supposed be able to solve y using "a similar method" according to one of my math teachers

Answer 5

@jiteshmeghwal9