Question

can some one help with this on 7y*8y

Answer 1

yes i can

Answer 2

ok

Answer 3

$7y\cdot\:8y=56y^2$7y· 8y=56y2

Steps

$7y\cdot\:8y$7y· 8y


$\mathrm{Multiply\:the\:numbers:}\:7\cdot\:8=56$Multiply the numbers: 7· 8=56

$=56yy$=56yy



$\mathrm{Apply\:exponent\:rule}:\quad\:a^b\cdot\:a^c=a^{b+c}$Apply exponent rule: ab· ac=ab+c

$yy=\:y^{1+1}=\:y^2$yy= y1+1= y2

$=56y^2$=56y​2

Answer 4

its -7y to the 7th power * 8y to the 4th power

Answer 5

u did not put that

Answer 6

you could use the equation editor (see the button in the lower left area below the input box)

\[ \left( -7y \right)^7 \cdot \left(8y\right)^4 \]

Answer 7

-7y^7(8y^4)

Answer 8

sorry I got the problem mixed upp

Answer 9

both are like terms with

Answer 10

$-7y^7\left(8y^4\right)$−7y7(8y4)


$\mathrm{Remove\:parentheses}:\quad\left(a\right)=a$Remove parentheses: (a)=a

$=-7y^7\cdot\:8y^4$=−7y7· 8y4



$\mathrm{Multiply\:the\:numbers:}\:7\cdot\:8=56$Multiply the numbers: 7· 8=56

$=-56y^7y^4$=−56y7y4



$\mathrm{Apply\:exponent\:rule}:\quad\:a^b\cdot\:a^c=a^{b+c}$Apply exponent rule: ab· ac=ab+c

$y^7y^4=\:y^{7+4}=\:y^{11}$y7y4= y7+4= y11

$=-56y^{11}$=−56y11

Answer 11

=−56y^11

Answer 12

thank you