Question

What is the best approximate for the blue shape’s area? The black dot just marks center, include it.

Answer 1

@KamiBug

Answer 2

Can you open that?

Answer 3

Yes. :) I'll brb!

Answer 4

Ok!

Answer 5

Okay, let's figure this out step by step...it's a bit tricky. XD
First let's find the area of the whole circle. Know how to do that?

Answer 6

Is that right..I think it is

Answer 7

Close. The 2 should actually be an exponent on radius. :) You have nice handwriting by the way ^.^ \[\pi * r^2\]

Answer 8

Thanks! lol

Answer 9

Np! :) So using that formula what do you get for area?

Answer 10

I am not sure! 20*12*2

Answer 11

The radius of the whole big circle can be found by taking half the diameter. The diameter is 20 so the radius is 10. Therefore
\[A = 3.14 * 10^2 \]

Answer 12

314

Answer 13

Right! Now let's pretend the smaller white circle in the middle doesn't have that rectangle in it and let's find it's area. Then we'll subtract that area from the area of the big circle and later we'll add back the area of the rectangle...does that make sense? Lol xD

Answer 14

The first part doesn't

Answer 15

Just explain the first part step through step and I will get it

Answer 16

Okay so what I mean is, let's find the area of the circle in the middle. X3 Lol
How do you think we can do that?

Answer 17

Im not sure

Answer 18

Just like we did with the bigger circle...we gotta use the radius... :)
The radius of the smaller circle is 6 bc the diameter is 12, see it ?

Answer 19

So 6*12^2

Answer 20

??

Answer 21

Not quite! Again, the formula for area of a circle is 3.14 * r^2
So it'd be 3.14 * 6^2

Answer 22

Oh ya

Answer 23

113.04

Answer 24

Right. Now let's subtract that from the first area we found. :)
314 - 113.04 = ?

Answer 25

200.96

Answer 26

Right! Now let's get the area of the rectangle and add it to that bc it's blue.

Answer 27

The area should be 36 because 3*12

Answer 28

Correct. :D So You answer should be 36 + 200.96 = ?

Answer 29

236.96! Thank you so much!!!

Answer 30

No problem! :D