1. Consider the system of equations. x-5y=2 3x-10y=11 (a) Jamar rewrote the first equation as –2x + 10y = –4. What justification did he have for doing this? (b) Jamar combined the equation in Part (a) with the second equation in the system to get x = 7. Explain Jamar’s reasoning. (c) What is the solution of the system? (d) How do you know, without graphing, that the graph of 4x – 15y = 13 passes through the point whose coordinates are the solution of the system?
hello
@freemap Compare the equation in part a with the first original equation. Original first equation: x - 5y = 2 Equation from part a: –2x + 10y = –4 What do you do to x to become -2x? What do you do to -5y to become 10y? What do you do to 2 to become -4? All questions above have the same answer. What is it?
please hold
@mathstudent55 same answer so add
No. Adding won't do it. There is no single quantity you can add in those three cases that will work. Try multiplication.
Yes, multiplication because 3(5y+2)
Where did you get that from?
What do you do multiply x by to get -2x? What do you do multiply -5y by to get 10y? What do you do multiply 2 by to get -4? All questions have the same answer.
3(5y+2)-10y=11 5y=5 y=1
You're using the substitution method, but this problem is not about substitution.
@mathstudent55 multiplying by 2
@jdoe0001
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I need part D @jdoe0001
I need part D @jhonyy9
ok. what is your opinon ,any idea about part D. ?
what mean eaxctly solution of a system ?
right.. what is the solution you've got from part 7c?
so, you're doing part D, so... we assume part 7c is already done
yes only need part D
@jhonyy9
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