4^3x-3= 10^7x-10

How can I solve this using logarithms?

Question

4^3x-3= 10^7x-10

How can I solve this using logarithms?

jhonyy9 · Answer

for eaxmple make ln on both sides 

ln (4^(3x-3) ) = ln (10^(7x-10))   so than what property of logarithms you know ? where go these exponents of 4 and on the other side of 10 ?

ohmath123 · Answer

I would have thought i would put log 4^(3x-3)= log 10^(7x-10) then the log 10 would cancel? @jhonyy9

jhonyy9 · Answer

no

you need to know that log a^x = xlog a

jhonyy9 · Answer

@Directrix do oyu have other way idea to solve it please ?

jhonyy9 · Answer

do you - sorry

directrix · Answer

I am not sure what the problem states.  No grouping symbols.

ohmath123 · Answer

the problem is telling me to solve for x but i have to use logarithms @Directrix @jhonyy9

jhonyy9 · Answer

you need to solve it for x - but the unknowed x there are in the exponents 

and this is again mistaque that the base numbers not are the same - so there are 4 and 10

directrix · Answer

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