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Use sum or difference identities to find the exact value of each trigonometric function: sinpie/2
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\[\sin(\frac{\pi}{2})\]?
yeah
you do not need an identity for this one, you should know this right off the bat
|dw:1457056060519:dw|
sine is the second coordinate
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find two angles that add up to pi/2 (or difference = pi/2) \[\large\rm Sin(a-b)=\sin a \cos b - \cos a \sin b\] 2pi -3pi/2 = pi/2 \[\sin (2\pi -\frac{3\pi}{2}) = \sin 2\pi \cdot \cos \frac{3\pi}{2}- \cos2 \pi \cdot \sin \frac{3\pi}{2}\] solve
|dw:1460035062976:dw| hang this on wall you still have to use unit circle but i think ur teacher wants to see the work
ok thanks
yw
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