question
\(\large \color{black}{\begin{align} & \normalsize \text{Ten students A, B, C, D, E, F, G, H, I and J}\hspace{.33em}\\~\\ & \normalsize \text{are chosen to represent their college in four sport}\hspace{.33em}\\~\\ & \normalsize \text{Tennis, badminton, table tennis, snooker.}\hspace{.33em}\\~\\ & \normalsize \text{The badminton team has one student less than tennis team.}\hspace{.33em}\\~\\ & \normalsize \text{A, B and C are not tennis player individually or as group.}\hspace{.33em}\\~\\ & \normalsize \text{D, E and F are not badminton player individually or as group.}\hspace{.33em}\\~\\ & \normalsize \text{G, H and I are not table tennis player individually or as group.}\hspace{.33em}\\~\\ & \normalsize \text{J is table tennis player.}\hspace{.33em}\\~\\ & \normalsize \text{None of the students is a snooker player.}\hspace{.33em}\\~\\ \end{align}}\) Which of the following students could be table tennis players a.) J,B and G b.) J,C and F c.) J,D,E and F d.) J,B,C and D
b lol
lol jk
answer is b.) but how u get it
it is ?
j and c can play tennis f is not badmitton so they play tennis
\(\begin{array}{|c|c|c|c|} \hline & \text{Tennis} & \text{Badminton}& \text{Table Tennis } \\ \hline A& \times & & \\ \hline B& \times & & \\ \hline C& \times & & \\ \hline D& & \times & \\ \hline E& & \times & \\ \hline F& &\times & \\ \hline G& & &\times \\ \hline H& & & \times \\ \hline I& & & \times \\ \hline J& \times & \times & \\ \hline Total & n & n-1 & & \\ \hline \end{array}\)
the table is given as hint
idk i guessed tbh
What happened to snooker?
college didn't have enough money
snooker = 0 ( no participants)
why is badminton \(n-1\), is that the rule?
I actually looked up this question in there is a text that says the answer is C. I don't get how they got it... There are 6 students we are still trying to place. So T,B,TT 6,5,... too many already throw this combination out 5,4,1 seems possible since J is a TT but we know there could be more because of the choices... 4,3,3 so 3 could play TT 2,1,7 ... 1,0,9 ... the last 2 don't make sense It seems it would be a chose with 3 people not 4 so I don't know how they got C
@ uncle due to this statement ->The badminton team has one student less than tennis team.
a choice with 3 people not 4*
i guess it say COULD... like there might be 3 people who actually play TT but we aren't given enough information to actually know the 3 people
like and some how are we can narrow it down to 4
it is like this text assumes a non tennis play is also a non-table tennis player
this question too confusing
yes ^ it is but i thought the table might somehow help to solve it
I'm not sure if this helps, but you can see that but an odd number of of students must play Table Tennis
I don't get the part "or as a group"
means A,B and C cannot be all in single team like tennis or badminton or table tennis
We have a total of 10 people. So far, we only know 1 person is in TT. That is J. We have 9 people left. Our answer choices gives either a total of 4 players or a total of 3 players. If we have a total of 4 players, then we will have 3 badminton and 3 tennis players. We cannot take 6 people and split them into the two teams so that one team has 1 person more than the other. If we have a total of 3 TT players, we can have a total of 7 tennis and badminton players. Do you see where I'm going with this? That means, we can then have 4 tennis players and 3 badminton players. Now, there are only 2 answer choices that have 3 players for TT. That is answer choice A and answer choice B. If you look at answer choice A, you can see that they say that G will be playing TT. But, we know from the question that G doesn't play. That leaves us with B as our answer. When I looked at this question, my mind was going all over. But the minute I started writing it down, it all become clear to me :) I hope this helps! If you have any questions, feel free to ask. :)
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