The data to the right comes from the last baseball season.
Wow. I certainly hope you're not in any kind of hurry :D I've figured it out, it's almost exactly like our previous problem, just, more work. Think of it as more exciting lol. You up for it?
yes of course
The only difference between this and our last problem (in essence) is that we don't have the venn diagram yet; we'll make it ourselves. Now, we could proceed without the Venn diagram, but I feel that would make life a lot easier. Ready to get drawing? XD
yes lol xD
|dw:1457103677081:dw| Let's do this
Could you, uhh, choose two letters, not A or B, because they're taken
|dw:1457107290719:dw|
idk lol any letter would be good :)
Hehe Miss Danielle (that's your name, right?) is getting ahead of herself again. Take a deep breath...
lol its a habit of mine in math xD and yes my name is Danielle
Pleasure. Despite my name and profile, my name is Kurt. Now, I like your initiative, but let me first point out WHY your idea is incorrect:
|dw:1457103884770:dw| I take it you meant this circle to represent those that made at least 20 home runs, yes?
yes
Unfortunately, if you really think about it, NOW, you've just made that equal to 35% instead of 28 as is written in your given :P Remember? To get P(B), you add ALL of the numbers in the circle. You have a 28 AND a 7 Not quite right, don't you think? ^^
oh so I have to subtract 7
I may not agree with your initiative all the time, but we can't deny that your instinct serves you well ^^ You're spot on :D The people who hit at least 20 home runs should be exactly 28%, and since you already have 7% accounted for, how much more are lacking?
21 and finally it pays off to get ahead of myself lol
Don't make it a habit, though :P Can't hurt to think carefully before you act :D Dammit, I'm having a hard time, so I'll assign letters myself X is the percent of those that have an average of at least 300 Y is the percent of those that have hit at least 20 home runs. So that we now have: |dw:1457104277382:dw| Can you fill in the rest of the X-circle?
|dw:1457107929494:dw|
Good. Now to the tricky part :D
We're considering two, uhh, situations. A: A player with an average of at least 300, will also hit at least 20 home runs So, it means, a player is already in X, we're checking the chances that the player is also in Y. That's the probability of Y, GIVEN that X is already true. Or P(Y|X) Look familiar?
7/21
1/3=0.33
No, lol, where the heck did you get 21? haha
omg sorry I got confused with the y instead of x hold on I got this
ok it would be 7+13=20 to get the whole x value then 7/20 to get x/y right?
X|Y It's a vertical bar, not a slanted one >:( LOL And yes, 7/20. Please express that in a percent ^^
35
and sorry lol I was just a bit too lazy
35% Good ^^ Now, look at scenario B. It's just the reverse. B: A player with at least 20 home runs, will also have an average of at least 300. You got this?
yes 7/28=25%
Brilliant. So. P(A) = P(Y|X) = 35% P(B) = P(X|Y) = 25% Think you can answer this now? :P
A is more likely than B?
Well done ^^
yay thank you! :D
thank yourself HAHA
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