A line with an inclination passes through (-5/2, -9/2), what is the x-coordinate of a point on the line if its corresponding y-coordinate is 6?
@Michele_Laino can you help me? :)
if we write the line3 as below: \[\Large ax + by + c = 0\] we get, by substitution: \[\Large 2c = 5a + 9b\] next I substitute \(y=6\) into the first equation: \[\Large a{x_0} + 6b + c = 0\] then I substitute \(c\): \[\Large a\left( {{x_0} + 5} \right) + 15b = 0\]
why did you put (Xo + 5 )?
@Michele_Laino
sorry I have made an error. If I substitute the value for \(c\), I get: \[\Large \begin{gathered} a{x_0} + 6b + \frac{{5a + 9b}}{2} = 0 \hfill \\ \hfill \\ 2a{x_0} + 12b + 5a + 9b = 0 \hfill \\ \hfill \\ a\left( {2{x_0} + 5} \right) + 21b = 0 \hfill \\ \end{gathered} \]
where \(x_0\) is the requested x-coordinates
x-coordinate*
then what should i do? i'm sorry :(
I also don't know I think that we need to know another quantity, for example, the slope of the line
for example, do the line pass at the origin \((0,0)\)
does*
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