Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

question attached in comments

OpenStudy (anonymous):

OpenStudy (anonymous):

Relation 1 is not a function because k has two different output values

OpenStudy (anonymous):

For a relation to be a function each input value must have one output value.

OpenStudy (anonymous):

Are you following me? Do you understand?

OpenStudy (anonymous):

Yes :) sorry for the late reply, i was switching classes

OpenStudy (anonymous):

Take a look at the first relation. K has two output values: sun and tree. So its not a function.

OpenStudy (anonymous):

actually, the website where i had the question just logged me out, so i lost the question. can i ask for your help on a different one?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

here it is! thanks

OpenStudy (anonymous):

The same question? You want to know which ones are functions?

OpenStudy (anonymous):

nevermind

OpenStudy (anonymous):

yes, i'm really confused

OpenStudy (anonymous):

Take a look at relation one. Does each value in the domain have one value in the range?

OpenStudy (anonymous):

those are different than the first picture

OpenStudy (anonymous):

yes, so it's a function, right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

that one is simple, but what about the other ones?

OpenStudy (anonymous):

Now take a look at relation 2. You have (-2 , C) and ( -2 , k)

OpenStudy (anonymous):

You have the same Domain value (-2), but two different range values (C) and (K)

OpenStudy (anonymous):

The domain is your input and the range your output. For a relation to be a function each input must have one output. So is relation 2 a function?

OpenStudy (anonymous):

no, it's not.

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

What do you think about relation 3?

OpenStudy (anonymous):

okay cool! let me try the other ones myself, and tell me if i'm correct.

OpenStudy (anonymous):

neither of the last two are functions.

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

okay, thank you so so much!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Mari103: How to pop out like a Jacc In the box
7 hours ago 0 Replies 0 Medals
Breathless: Spooky witch but cute
14 hours ago 3 Replies 0 Medals
Arriyanalol: help
14 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
17 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
17 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!