Question

PLZ HELP ME!!!!!!!!!!!!
If (6y-11)(6y+11)=ay^2-b, what is the value of a?

Answer 1

Do you remember that property:
(a+b)(a-b)=a^2-b^2

Answer 2

Sort of nit really

Answer 3

Hint: (a-b)(a+b) = a^2 - b^2

Answer 4

ah you beat me to it!

Answer 5

*not

Answer 6

halp meeeeee

Answer 7

Just apply it to the exercise

Answer 8

Ohhhh
Is it 6?

Answer 9

Or 6y?

Answer 10

It would be the square of 6

Answer 11

So, basically to solve your question, you have 6y as a.

And then you have (6y)^2 = ay^2

So what is a?

Answer 12

(6y)^2 = ay^2

Solve forma.

Answer 13

-85????

Answer 14

Solve for a*

Answer 15

@mathgirl_123 what did you do to get that number? It's wrong btw.

Answer 16

mathway.com

Answer 17

I'm getting 6y idk what I'm doing wrong

Answer 18

Ok, ok.

What is (6y)^2 = ??

Answer 19

36y

Answer 20

Also, you're not telling us what you are doing so we don't know what you're doing wrong.

Answer 21

No, (6y)^2 = 36y^2

So we have

36y^2 = ay^2

Can you tell me what a is?

Answer 22

(6y)^2=36y

Answer 23

No, it doesn't.

(ab)^2 =a^2b^2

Answer 24

Don't you divide 36y^2 by a which is 6y?

Answer 25

.

Answer 26

No...

36y^2 = ay^2

What happens when you divide both sides by y^2? What are you left with?

Answer 27

I am so sorry I'm having like a blank brain moment I am so confused

Answer 28

I bet the answer is really obvious idk why I can't figure it out

Answer 29

.

Answer 30

Is it 36?

Answer 31

It is. :)