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OpenStudy (tylermckinney16):
Questions here.
OpenStudy (jdoe0001):
\(\bf \textit{volume of a pyramid}=\cfrac{1}{3}{\color{brown}{ base}}\cdot height\)
if you solve that for "height", you'd get the .. well, height :)
what's the base of that pyramid? well, is a 8*12 rectangle, that is |dw:1457135822540:dw|
so, you have the base, and the volume, use that to get the height :)
rebeccaxhawaii (rebeccaxhawaii):
^^
OpenStudy (tylermckinney16):
@KamiBug
OpenStudy (kamibug):
Base : 8*12 = 96
\[224 = \frac{ 1 }{ 3 }*96*h\]
Can you solve that for h?
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OpenStudy (tylermckinney16):
yeah :)
OpenStudy (kamibug):
Ok great. ^_^
OpenStudy (tylermckinney16):
wait can you explain the first step to find h?
OpenStudy (kamibug):
You can multiply both sides by 3 first to cancel out the fraction.
OpenStudy (tylermckinney16):
ok cool :)
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OpenStudy (tylermckinney16):
8*3=24
12*3=36
Like this?
@KamiBug
OpenStudy (tylermckinney16):
@Directrix
OpenStudy (jdoe0001):
hmmm what did you get for the base anyway?
OpenStudy (kamibug):
@TylerMckinney16 No, don't worry about the 8 and 12 anymore we already multiplied those and got the base of 96 in the equation. :P
Focus on what we've filled in the formula...like this... :D|dw:1457152924772:dw|