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Please help x-4/5=6/13
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add -4/5 to both sides
you should add +4/5 to the both sides
\(\bf x-\cfrac{4}{5}=\cfrac{6}{13}\qquad or\qquad \cfrac{x-4}{5}=\cfrac{6}{13}?\)
Oh, 2nd one
then just cross-multiply and siimplify
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Ok, can you help me with that?
\(\bf \cfrac{x-4}{{\color{blue}{ 5}}}=\cfrac{6}{{\color{brown}{ 13}}}\implies {\color{brown}{ 13}}(x-4)={\color{blue}{ 5}}(6)\) expand both sides
Ok, what do I do about (x-4) though?
distribute the 13 to it :/
Alright, thanks.
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yw
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