p^2+8p+64. This problem has to be solved using the quadratic formula. I know the answer is -1 plus/minus the square root of 3i, but i have no idea how to get there. please help. if it helps this problem comes from p^6-9p^3+8=0
Okay well do you remember what the quadratic formula is?
And also, although its in terms of p and the formula its self is generally written in x you can just change the p to x and then change it back to p after using it.
Or i'm sorry written in terms of b a and c. thinking of something else :P
x =-b +- the square root of b^2-4ac/2a
Instead of giving it to him let him find it out himself. I was getting to that.
yes. I applied it to the equation, but apparently there seems to be more steps involved. Other answers say that its −4±4i√3, but on mathlab it seems to be more specific.
Did they specify on a certain form or?
i know the quadratic formula has to be used to get the answer. i can draw it on here.
ok sure, show the steps.
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