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need help with trigonometry http://prnt.sc/abj7ta
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where is Q
that is all the info i was given
yes, your answer looks correct to find the period you match up \[ \frac{2 \pi }{T} \theta = \frac{1}{2}\theta \] T is the period. in other words, we solve for T in \[ \frac{2 \pi }{T} =\frac{1}{2} \\ T= 4 \pi = 720º \]
thanks
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