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Mathematics 14 Online
OpenStudy (anonymous):

HELP The function H(t)=-16t^2+90t+50 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t)= 28+48.8t, where g(t) is the height, in feet, of the on object from the ground at time t seconds. Part A) Create a table using integers 1 though 4 for the 2 functions. Between what 2 seconds is the solutions is the solution to H(t)=g(t) located? How do you know? Part B) Explain what the solution from Part A means in the context of the problem

OpenStudy (lolacole12):

H(t)=-16t^2+90t+50

OpenStudy (lolacole12):

Right≥﹏≤

OpenStudy (anonymous):

oh sorry let me check

OpenStudy (anonymous):

yes

OpenStudy (lolacole12):

Ok

OpenStudy (anonymous):

Im lost and I have almost no idea what this question is asking me please help!

OpenStudy (anonymous):

They want you to create a table of values for x = 1 through 4 for both functions. Then compare them and see where they are equal.

OpenStudy (anonymous):

Or I guess I should have said t = 1 through 4.

OpenStudy (anonymous):

hmmm and after that? Do they want me to do the same for the second function?

OpenStudy (anonymous):

Yes, calculate 1 through 4 for both functions. Then compare them.

OpenStudy (anonymous):

okay and after i compare them?

OpenStudy (anonymous):

Your comparing them to see where they are equal.

OpenStudy (anonymous):

what is the goal for answering this question? (sorry for a lack of a better word)

OpenStudy (anonymous):

You want to find where they meet.

OpenStudy (anonymous):

"Between what 2 seconds is the solutions to H(t)=g(t) located? How do you know?" is mostly what I'm a little confused for. so this "Between what 2 seconds is the solutions to H(t)=g(t) located" means i have to find where they meet

OpenStudy (anonymous):

so i have to make 2 tables with the 1 to 4 thing then the number that is closest to each other is the answer?

OpenStudy (anonymous):

Yeah, make a table for both and compare the tables to see where they are close to each other

OpenStudy (anonymous):

when i do find the answer then what does that mean for part B?

OpenStudy (anonymous):

I think it means they are at the same height

OpenStudy (anonymous):

Okay I see. Can i shout you out if i run into any bumps?

OpenStudy (anonymous):

Can you graph the two equations? The batteries in my calculator are dead.

OpenStudy (anonymous):

let me see

OpenStudy (anonymous):

by the way it seems the numbers down seem to be not that close to each other

OpenStudy (anonymous):

The problem says they meet somewhere between two seconds

OpenStudy (anonymous):

I cant graph them >.<

OpenStudy (anonymous):

i have 16t^2+90+50 (1) 156 (2) 262 (3) 368 (4) 474 and g(t) 28+ 48.8t (1) 76.8 (2) 125.6 (3)174.4 (4) 223.2

OpenStudy (anonymous):

give me a sec

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

(1,124) (2, 166) (3, 176) (4, 154) for the coordinates of the first graph

OpenStudy (anonymous):

Your Y coordinates are off because you used 16 instead of -16

OpenStudy (anonymous):

aww man >.<

OpenStudy (anonymous):

the coordinates for the second graph are correct. So take a look at where they come close to each other.

OpenStudy (anonymous):

(1, 124) (2, 166) (3, 176) (4, 154) (1, 76.8) (2,125.6) (3,174.4) (4, 223.2)

OpenStudy (anonymous):

3rd one?

OpenStudy (anonymous):

Yes. But the question asked between what 2 seconds.

OpenStudy (anonymous):

At the 3 second mark the second projectile is slightly lower than the first.

OpenStudy (anonymous):

what does this mean then?

OpenStudy (anonymous):

It means it takes more than 3 seconds.

OpenStudy (anonymous):

So between what 2 seconds do they cross paths?

OpenStudy (anonymous):

Hmmm... I not sure ....

OpenStudy (anonymous):

If it takes more than 3 seconds but less than 4 seconds

OpenStudy (anonymous):

What two seconds is it between?

OpenStudy (anonymous):

OH gosh i really don't know I'm sorry the only thing i can think of is like 3.5

OpenStudy (anonymous):

It's not asking for an exact answer. Its asking between what 2 seconds the projectiles meet.

OpenStudy (anonymous):

You know like between second 1 and 2.

OpenStudy (anonymous):

And we know our projectiles are very near each other at the 3 second mark.

OpenStudy (anonymous):

So it takes over 3 seconds for them to reach each other.

OpenStudy (anonymous):

But less than 4 seconds

OpenStudy (anonymous):

So they meet between what 2 seconds?

OpenStudy (anonymous):

its between the 124 and 125.6 points on the table?

OpenStudy (anonymous):

(3, 176) (4, 154) (3,174.4) (4, 223.2)

OpenStudy (anonymous):

ohhhh, duh so this is the answer. I was thinking about this too hard

OpenStudy (anonymous):

Do you see how close the y coordinates are at 3? Now take a look at 4? They've passed each other. So between what two seconds do they meet?

OpenStudy (anonymous):

(3, 176) (3,174.4)?

OpenStudy (anonymous):

Yes thats their coordinates at the 3 second mark. So it takes more than 3 seconds for them to meet. Theyve already passed each other at the 4 second mark. So between what two seconds do they meet?

OpenStudy (anonymous):

They meet between the 3rd and 4th second.

OpenStudy (anonymous):

Do you see that?

OpenStudy (anonymous):

tes

OpenStudy (anonymous):

*yes

OpenStudy (anonymous):

so for part A is that the objects are at the same height between 3 and 4 seconds.

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

They are crossing paths or colliding at the 3 second mark

OpenStudy (anonymous):

would that be also the answer for part b then?

OpenStudy (anonymous):

And thats basically what part B is asking you. What are they doing between the 3rd and 4th seconds.

OpenStudy (anonymous):

ohh okay ...

OpenStudy (anonymous):

Pretty much, yeah. Part A also asks how you know they are crossing paths. You know that because of

OpenStudy (anonymous):

You know the coordinates are close to each other right?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

so i know this because of the coordinates?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

ok i see. Thank you very much. Wouldn't have gotten it without your help! Thank you!

OpenStudy (anonymous):

no problem

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