HELP The function H(t)=-16t^2+90t+50 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t)= 28+48.8t, where g(t) is the height, in feet, of the on object from the ground at time t seconds. Part A) Create a table using integers 1 though 4 for the 2 functions. Between what 2 seconds is the solutions is the solution to H(t)=g(t) located? How do you know? Part B) Explain what the solution from Part A means in the context of the problem
H(t)=-16t^2+90t+50
Right≥﹏≤
oh sorry let me check
yes
Ok
Im lost and I have almost no idea what this question is asking me please help!
They want you to create a table of values for x = 1 through 4 for both functions. Then compare them and see where they are equal.
Or I guess I should have said t = 1 through 4.
hmmm and after that? Do they want me to do the same for the second function?
Yes, calculate 1 through 4 for both functions. Then compare them.
okay and after i compare them?
Your comparing them to see where they are equal.
what is the goal for answering this question? (sorry for a lack of a better word)
You want to find where they meet.
"Between what 2 seconds is the solutions to H(t)=g(t) located? How do you know?" is mostly what I'm a little confused for. so this "Between what 2 seconds is the solutions to H(t)=g(t) located" means i have to find where they meet
so i have to make 2 tables with the 1 to 4 thing then the number that is closest to each other is the answer?
Yeah, make a table for both and compare the tables to see where they are close to each other
when i do find the answer then what does that mean for part B?
I think it means they are at the same height
Okay I see. Can i shout you out if i run into any bumps?
Can you graph the two equations? The batteries in my calculator are dead.
let me see
by the way it seems the numbers down seem to be not that close to each other
The problem says they meet somewhere between two seconds
I cant graph them >.<
i have 16t^2+90+50 (1) 156 (2) 262 (3) 368 (4) 474 and g(t) 28+ 48.8t (1) 76.8 (2) 125.6 (3)174.4 (4) 223.2
give me a sec
ok
(1,124) (2, 166) (3, 176) (4, 154) for the coordinates of the first graph
Your Y coordinates are off because you used 16 instead of -16
aww man >.<
the coordinates for the second graph are correct. So take a look at where they come close to each other.
(1, 124) (2, 166) (3, 176) (4, 154) (1, 76.8) (2,125.6) (3,174.4) (4, 223.2)
3rd one?
Yes. But the question asked between what 2 seconds.
At the 3 second mark the second projectile is slightly lower than the first.
what does this mean then?
It means it takes more than 3 seconds.
So between what 2 seconds do they cross paths?
Hmmm... I not sure ....
If it takes more than 3 seconds but less than 4 seconds
What two seconds is it between?
OH gosh i really don't know I'm sorry the only thing i can think of is like 3.5
It's not asking for an exact answer. Its asking between what 2 seconds the projectiles meet.
You know like between second 1 and 2.
And we know our projectiles are very near each other at the 3 second mark.
So it takes over 3 seconds for them to reach each other.
But less than 4 seconds
So they meet between what 2 seconds?
its between the 124 and 125.6 points on the table?
(3, 176) (4, 154) (3,174.4) (4, 223.2)
ohhhh, duh so this is the answer. I was thinking about this too hard
Do you see how close the y coordinates are at 3? Now take a look at 4? They've passed each other. So between what two seconds do they meet?
(3, 176) (3,174.4)?
Yes thats their coordinates at the 3 second mark. So it takes more than 3 seconds for them to meet. Theyve already passed each other at the 4 second mark. So between what two seconds do they meet?
They meet between the 3rd and 4th second.
Do you see that?
tes
*yes
so for part A is that the objects are at the same height between 3 and 4 seconds.
Yes
They are crossing paths or colliding at the 3 second mark
would that be also the answer for part b then?
And thats basically what part B is asking you. What are they doing between the 3rd and 4th seconds.
ohh okay ...
Pretty much, yeah. Part A also asks how you know they are crossing paths. You know that because of
You know the coordinates are close to each other right?
yea
so i know this because of the coordinates?
yup
ok i see. Thank you very much. Wouldn't have gotten it without your help! Thank you!
no problem
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