Simplify expression
(3x^4 + 9x^3 – 7x + 15) + (–6x^4 – 8x^2 + 5x – 3)
@hartnn
add like terms
(3x^4+6x^4)+(5x-3)...?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @shaleiah (3x^4 + 9x^3 – 7x + 15) + (–6x^4 – 8x^2 + 5x – 3) \(\color{#0cbb34}{\text{End of Quote}}\) x^4 terms: 3x^4, -6x^4 >>> 3x^4-6x^4 = (3-6)x^4 = -3x^4 got this? x^3 terms: +9x^3 can you do the same for x^2 terms?
there is only one 'x^2' term, -8x^2 so keep it as it is. what are 'x' terms?
(7x+5+5x-3)
(3x^4 + 9x^3 \(\Large \color{red}– 7x\) + 15) + (–6x^4 – 8x^2 \(\Large\color{red}+ 5x\) – 3) -7x +5x = (-7+5)x
lastly, all the constants, 15-3 = ...
12
so lets put everything together (3x^4 + 9x^3 – 7x + 15) + (–6x^4 – 8x^2 + 5x – 3) \(\Huge 3x^4-6x^4 = -3x^4\) \(\LARGE \color{red}{ 9x^3}\) \(\Large -8x^2\) \(-7x+5x = -2x \\15-3=12\) \(\implies -3x^4-8x^2 -2x+12\) any doubts?
Got it :)
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