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Mathematics 16 Online
OpenStudy (candy13106):

consider the polynomial function f(x)=x^3-5x^2-12x+36. A) given that f(2)=0, find the other zeros of f. B)Based on your results from part a , what are the factors of the polynomial x^3-5x^2-12x+36 c) what are the solutions of the polynomial equation x^3-5x^2-12x+36=0

OpenStudy (sweetburger):

Given A) that means you can factor out (x-2) from x^3-5x^2-12x+36.

OpenStudy (sweetburger):

then you can factor the result of that to determine what other 0's exist.

OpenStudy (candy13106):

ok

OpenStudy (candy13106):

so wat do i do next

OpenStudy (candy13106):

@sweetburger

OpenStudy (hybrik):

Or what I would do is divide x-2 off of x^3-5x^2-12+36, since x-2 is a root of the equation (f(2)=0)

OpenStudy (hybrik):

You can use synthetic division for this.

OpenStudy (candy13106):

ok wait ill do it

OpenStudy (hybrik):

You can use synthetic division for this.

OpenStudy (candy13106):

ok so i got x^2-7x-26

OpenStudy (hybrik):

Okay, solve that equation to find the other zeroes.

OpenStudy (candy13106):

how would i do that

OpenStudy (hybrik):

You can use the quadratic equation: \[x=-b \pm \sqrt{b^2-4ac} \] all over 2a

OpenStudy (candy13106):

ok

OpenStudy (candy13106):

ok i got 7+ or - the square root of 153 divide 2

OpenStudy (hybrik):

Okay, I don't think that equation is correct earlier, the x^2-7x-26. Did you do your division correctly?

OpenStudy (hybrik):

Because when I did the division, I got x^2-3x-18=0.

OpenStudy (hybrik):

Check your division.

OpenStudy (candy13106):

ok

OpenStudy (candy13106):

-5-2 is -7 not -3

OpenStudy (hybrik):

The division your not dividing by -2, your dividing by 2.

OpenStudy (candy13106):

ok so i did it wrong and now i got wat u got and then i did the quadratic formula and got 3+of - 9 divide 2

OpenStudy (hybrik):

You can simplify that answer, two answers are given. (3+9)/2 and (3-9)/2

OpenStudy (candy13106):

ok i will do that

OpenStudy (candy13106):

x=6 and x=-3

OpenStudy (hybrik):

Okay, the zeroes are: 2(given zero), 6, and -3.

OpenStudy (hybrik):

A would be the two roots, 6 and -3.

OpenStudy (candy13106):

k

OpenStudy (candy13106):

so wat would i do to find b

OpenStudy (hybrik):

The factors are the zeroes, but subtracting where (x-q) would be a factor, q would be the root.

OpenStudy (hybrik):

For example, one of the given roots were 2. A factor form would be (x-2).

OpenStudy (hybrik):

What would be the other two?

OpenStudy (candy13106):

ok im confused

OpenStudy (hybrik):

Lets say you want to factor x^2-4x+4

OpenStudy (candy13106):

k

OpenStudy (hybrik):

First, you would need to know the zeroes, which would be -2.

OpenStudy (candy13106):

so wat would i do

OpenStudy (hybrik):

You have to put the equation in the form (x-q)(x-r)(x-s)

OpenStudy (hybrik):

Where q r and s are the zeroes of the equation.

OpenStudy (candy13106):

ok so (x-2)(x-6)(x--3)

OpenStudy (hybrik):

Yes.

OpenStudy (candy13106):

ok so i just multiply them

OpenStudy (hybrik):

No, multiplying them will give you your original equation.

OpenStudy (hybrik):

You leave it like that.

OpenStudy (candy13106):

for part b?

OpenStudy (hybrik):

Yes.

OpenStudy (candy13106):

ok then wat would i do for part c

OpenStudy (hybrik):

Part C is asking you for the zeroes, which we've already found. What would they be?

OpenStudy (candy13106):

2,6,3

OpenStudy (hybrik):

2,6,-3 you mean.

OpenStudy (candy13106):

yea

OpenStudy (hybrik):

yea, those would be the roots.

OpenStudy (candy13106):

ok thanks

OpenStudy (hybrik):

your welcome

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