consider the polynomial function f(x)=x^3-5x^2-12x+36.
A) given that f(2)=0, find the other zeros of f.
B)Based on your results from part a , what are the factors of the polynomial x^3-5x^2-12x+36
c) what are the solutions of the polynomial equation x^3-5x^2-12x+36=0
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OpenStudy (sweetburger):
Given A) that means you can factor out (x-2) from x^3-5x^2-12x+36.
OpenStudy (sweetburger):
then you can factor the result of that to determine what other 0's exist.
OpenStudy (candy13106):
ok
OpenStudy (candy13106):
so wat do i do next
OpenStudy (candy13106):
@sweetburger
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OpenStudy (hybrik):
Or what I would do is divide x-2 off of x^3-5x^2-12+36, since x-2 is a root of the equation (f(2)=0)
OpenStudy (hybrik):
You can use synthetic division for this.
OpenStudy (candy13106):
ok wait ill do it
OpenStudy (hybrik):
You can use synthetic division for this.
OpenStudy (candy13106):
ok so i got x^2-7x-26
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OpenStudy (hybrik):
Okay, solve that equation to find the other zeroes.
OpenStudy (candy13106):
how would i do that
OpenStudy (hybrik):
You can use the quadratic equation: \[x=-b \pm \sqrt{b^2-4ac} \] all over 2a
OpenStudy (candy13106):
ok
OpenStudy (candy13106):
ok i got 7+ or - the square root of 153 divide 2
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OpenStudy (hybrik):
Okay, I don't think that equation is correct earlier, the x^2-7x-26. Did you do your division correctly?
OpenStudy (hybrik):
Because when I did the division, I got x^2-3x-18=0.
OpenStudy (hybrik):
Check your division.
OpenStudy (candy13106):
ok
OpenStudy (candy13106):
-5-2 is -7 not -3
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OpenStudy (hybrik):
The division your not dividing by -2, your dividing by 2.
OpenStudy (candy13106):
ok so i did it wrong and now i got wat u got and then i did the quadratic formula and got 3+of - 9 divide 2
OpenStudy (hybrik):
You can simplify that answer, two answers are given. (3+9)/2 and (3-9)/2
OpenStudy (candy13106):
ok i will do that
OpenStudy (candy13106):
x=6 and x=-3
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OpenStudy (hybrik):
Okay, the zeroes are: 2(given zero), 6, and -3.
OpenStudy (hybrik):
A would be the two roots, 6 and -3.
OpenStudy (candy13106):
k
OpenStudy (candy13106):
so wat would i do to find b
OpenStudy (hybrik):
The factors are the zeroes, but subtracting where (x-q) would be a factor, q would be the root.
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OpenStudy (hybrik):
For example, one of the given roots were 2. A factor form would be (x-2).
OpenStudy (hybrik):
What would be the other two?
OpenStudy (candy13106):
ok im confused
OpenStudy (hybrik):
Lets say you want to factor x^2-4x+4
OpenStudy (candy13106):
k
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OpenStudy (hybrik):
First, you would need to know the zeroes, which would be -2.
OpenStudy (candy13106):
so wat would i do
OpenStudy (hybrik):
You have to put the equation in the form (x-q)(x-r)(x-s)
OpenStudy (hybrik):
Where q r and s are the zeroes of the equation.
OpenStudy (candy13106):
ok so (x-2)(x-6)(x--3)
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OpenStudy (hybrik):
Yes.
OpenStudy (candy13106):
ok so i just multiply them
OpenStudy (hybrik):
No, multiplying them will give you your original equation.
OpenStudy (hybrik):
You leave it like that.
OpenStudy (candy13106):
for part b?
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OpenStudy (hybrik):
Yes.
OpenStudy (candy13106):
ok then wat would i do for part c
OpenStudy (hybrik):
Part C is asking you for the zeroes, which we've already found. What would they be?
OpenStudy (candy13106):
2,6,3
OpenStudy (hybrik):
2,6,-3 you mean.
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