Question

If 125 cal of heat is applied to a 60.0-g piece of copper at 24.0 ∘C , what will the final temperature be? The specific heat of copper is 0.0920 cal/(g⋅∘C)

Answer 1

\[q=mc \Delta T\]

Answer 2

You are given C, the specific heat. You are given m, the mass. You are given q, the heat applied/transferred. You need to solve for Delta T which is the change in temperature. Note: this is not your final answer. You need to add the change in temperature to you initial temperature.