Question

A child throws a ball with a velocity of 1.93 m/s [horizontally] at a height of 0.75 m. If air resistance is negligible, the horizontal range of the ball is:
Question 6 options:

A) 0.30 m

B) 4.9 m

C) 0.76 m

D) 0.20 m

E) 0.73 m

Answer 1

@Astrophysics @Vincent-Lyon.Fr

Answer 2

@study_buddy99 @yaya090600 @ltrout @Sienna_Kate

Answer 3

@ganeshie8 @Preetha @ParthKohli @Kainui @Kkutie7

Answer 4

@baru @Irrati0nal

Answer 5

first find time(t) required for an object to free fall from a height of 0.75m
(use s=1/2gt^2)

Answer 6

1.93*t gives the required answer

Answer 7

g be 9.8 m/s right?

Answer 8

yes

Answer 9

well i am getting 18.25

Answer 10

\[0.75=0.5 \times 9.8 \times t^2\]

Answer 11

t=0.39

Answer 12

so for finding the time you divide 0.75/1.93 which gives 0.39 right?

Answer 13

no

Answer 14

we get 't' from solving this equation\[0.75=0.5 \times 9.8 \times t^2\]

Answer 15

\[t=\sqrt{\frac{0.75}{0.5\times 9.8} }\]

Answer 16

why did you put square root?

Answer 17

after finding 't'
multiply 1.93 X t to find "range"

Answer 18

the formula has t square, (\(t^2\))

Answer 19

oh yeah

Answer 20

so know we have to multiply 1.93x0.39

Answer 21

yes

Answer 22

i get 0.7527

Answer 23

option C is the closest match

Answer 24

yeah

Answer 25

@baru thanks a lot

Answer 26

no problem :)