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Mathematics 19 Online
OpenStudy (study_buddy99):

Algebra II help? Rational equations?

OpenStudy (study_buddy99):

\[b+\frac{ 2b }{ b-1 }=1-\frac{ b-3 }{ b-1 }\]

OpenStudy (study_buddy99):

I keep getting b^2+b+4

OpenStudy (anonymous):

You should get b^2 - b - 2

OpenStudy (anonymous):

Did you distribute this correct \[-(\frac{b-3}{b-1})\]

OpenStudy (study_buddy99):

I shouldn't have to? I'm canceling the b-1

OpenStudy (anonymous):

Once you cancel b-1 you are left with \[-(b-3)\] did you expand it like \[-b + 3\]

OpenStudy (study_buddy99):

I shouldn't have to? I'm canceling the b-1

OpenStudy (study_buddy99):

I got it! I distributed wrong!

OpenStudy (anonymous):

That's right

OpenStudy (study_buddy99):

how'd you get -b

OpenStudy (anonymous):

(b-1)b+2b = 1(b-1)-(b-3)

OpenStudy (anonymous):

b^2-b+2b=b-1-b+3 (b in the right side and -b gets cancelled) b^2 +b-2

OpenStudy (anonymous):

I am sorry it should be +b

OpenStudy (study_buddy99):

haha, okay... Good news: I'm not crazy! so then how do you get the answer from \[b^2+b+2\]

OpenStudy (anonymous):

it should be -2

OpenStudy (study_buddy99):

there we go :) I fixed it

OpenStudy (study_buddy99):

... and I still got the wrong answer >_<

OpenStudy (anonymous):

So b^2+2b-b+2=0 b(b+2)-1(b+2)=0 (b-1)(b+2)=0 b=1 and b=-2

OpenStudy (study_buddy99):

aha thanks once again!

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