Mathematics
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OpenStudy (study_buddy99):
Algebra II help? Rational equations?
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OpenStudy (study_buddy99):
\[b+\frac{ 2b }{ b-1 }=1-\frac{ b-3 }{ b-1 }\]
OpenStudy (study_buddy99):
I keep getting b^2+b+4
OpenStudy (anonymous):
You should get b^2 - b - 2
OpenStudy (anonymous):
Did you distribute this correct
\[-(\frac{b-3}{b-1})\]
OpenStudy (study_buddy99):
I shouldn't have to? I'm canceling the b-1
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OpenStudy (anonymous):
Once you cancel b-1 you are left with
\[-(b-3)\]
did you expand it like
\[-b + 3\]
OpenStudy (study_buddy99):
I shouldn't have to? I'm canceling the b-1
OpenStudy (study_buddy99):
I got it! I distributed wrong!
OpenStudy (anonymous):
That's right
OpenStudy (study_buddy99):
how'd you get -b
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OpenStudy (anonymous):
(b-1)b+2b = 1(b-1)-(b-3)
OpenStudy (anonymous):
b^2-b+2b=b-1-b+3 (b in the right side and -b gets cancelled)
b^2 +b-2
OpenStudy (anonymous):
I am sorry it should be +b
OpenStudy (study_buddy99):
haha, okay... Good news: I'm not crazy! so then how do you get the answer from \[b^2+b+2\]
OpenStudy (anonymous):
it should be -2
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OpenStudy (study_buddy99):
there we go :) I fixed it
OpenStudy (study_buddy99):
... and I still got the wrong answer >_<
OpenStudy (anonymous):
So
b^2+2b-b+2=0
b(b+2)-1(b+2)=0
(b-1)(b+2)=0
b=1 and b=-2
OpenStudy (study_buddy99):
aha thanks once again!