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Can someone check my answer real quick?
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Use one variable to write a definite integral whose value equals the volume of the solid when y = tan x and is rotated around the line x = -1
Forgot the put the bounds above, but it's 0 to 1 \[\pi \int\limits_{0}^{1} (1+x) \tan (x) dx\] Is this correct? If not, why?
By shells : \[dV = 2\pi r *y *dx = 2\pi (1+x)*\tan x *dx\]
integrate that between x=0 and x=1 to get he entire volume : \[V = \int\limits_0^1 dV = \int\limits_0^1 2\pi (1+x)*\tan x *dx\]
Looks you're missing a \(2\)
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