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Mathematics 17 Online
OpenStudy (jojokiw3):

Can someone check my answer real quick?

OpenStudy (jojokiw3):

Use one variable to write a definite integral whose value equals the volume of the solid when y = tan x and is rotated around the line x = -1

OpenStudy (jojokiw3):

Forgot the put the bounds above, but it's 0 to 1 \[\pi \int\limits_{0}^{1} (1+x) \tan (x) dx\] Is this correct? If not, why?

ganeshie8 (ganeshie8):

By shells : \[dV = 2\pi r *y *dx = 2\pi (1+x)*\tan x *dx\]

ganeshie8 (ganeshie8):

integrate that between x=0 and x=1 to get he entire volume : \[V = \int\limits_0^1 dV = \int\limits_0^1 2\pi (1+x)*\tan x *dx\]

ganeshie8 (ganeshie8):

Looks you're missing a \(2\)

OpenStudy (anonymous):

ill help

OpenStudy (anonymous):

ill help

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