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If cos(θ) = -5/17 and θ is in quadrant III, find sin(θ). Give your answer to four decimal places. If sin(θ) = -15/17 and θ is in quadrant III, find cos(θ). Give your answer to four decimal places.
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|dw:1457369999080:dw|
So I have to figure out what x is?
Yes - use pythagoras the sine will be x / 17
cosine is adjacent / hypotenuse ?
-5 / 17
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yes - and sine = opposite / hypotenuse
x = - sqrt(17^2 - 5^2)
-16.2481
yes
now do I do the same thing for the second problem
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similar thing yea
sine is opposite / hypotenuse?
right
|dw:1457370698276:dw|
is that how it would be?
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yea
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