I use a thermometer graduated in 1/5 degree Celsius to measure outside air temperature. Measured to the nearest 1/5 degree, yesterday's temperature was 22.4 degrees Celsius and today's is 24.8 degrees Celsius. What is the relative uncertainty in the temperature difference between yesterday and today?
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OpenStudy (diamondboy):
I got 16.7 percent
OpenStudy (diamondboy):
@Michele_Laino
OpenStudy (diamondboy):
@freckles
OpenStudy (diamondboy):
@Preetha
OpenStudy (diamondboy):
@SolomonZelman
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OpenStudy (diamondboy):
can you help @jdoe0001
OpenStudy (diamondboy):
I would medal
OpenStudy (diamondboy):
@phi
OpenStudy (phi):
I am thinking the temp difference is 2.4 deg
the uncertainty is 0.2 on the first measurement and 0.2 on the 2nd
so the relative uncertainty *might* be 0.4/2.4
however, I think people combine uncertainty to get sqr(2) * 0.2 (rather that 2*0.2)
if that is correct (I'm a bit hazy on this), you would get 0.2828/2.4 = 11.8%
OpenStudy (diamondboy):
the answer is actually 7.7 perccent
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OpenStudy (phi):
If you know how they got that number, please post the math