I use a thermometer graduated in 1/5 degree Celsius to measure outside air temperature. Measured to the nearest 1/5 degree, yesterday's temperature was 22.4 degrees Celsius and today's is 24.8 degrees Celsius. What is the relative uncertainty in the temperature difference between yesterday and today?
I got 16.7 percent
@Michele_Laino
@freckles
@Preetha
@SolomonZelman
can you help @jdoe0001
I would medal
@phi
I am thinking the temp difference is 2.4 deg the uncertainty is 0.2 on the first measurement and 0.2 on the 2nd so the relative uncertainty *might* be 0.4/2.4 however, I think people combine uncertainty to get sqr(2) * 0.2 (rather that 2*0.2) if that is correct (I'm a bit hazy on this), you would get 0.2828/2.4 = 11.8%
the answer is actually 7.7 perccent
If you know how they got that number, please post the math
ok. I would figure it out
24,8-22,4=2,4 22,4 ---- 100% 2,4 ----- x% ----------------- x = 2,4*100/22,4 = 10,71 %
wrong
I am sorry
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