PRE-CALC HNRS
I need help understanding this pre-calc Hnrs example problem. I was understanding it until they got to the .76 and the b1 and b2. How did they get the two degrees from .76? I'll post more below.

Question

PRE-CALC HNRS
I need help understanding this pre-calc Hnrs example problem. I was understanding it until they got to the .76 and the b1 and b2. How did they get the two degrees from .76? I'll post more below.

anonymous · Answer

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anonymous · Answer

It's for pre-calc 6.01 Law of Sines.

mathmusician · Answer

Hey

mathmusician · Answer

Okay so you have to use the equations that they gave you

mathmusician · Answer

tell me what is given

anonymous · Answer

a = 6, b = 8, and A = 35°

mathmusician · Answer

Do you know how to use the equations

mathmusician · Answer

Well if sinB is .76 thenyou could just use the inverse of sin to find b

mathmusician · Answer

Do you know what this means $$\sin ^{-1}x$$

anonymous · Answer

Yes, I understand they used a/Sin A = b/SinB. Yes, that's the inverse sine right?

mathmusician · Answer

Yes so after using the inverse of sin we get about 49 degrees 49.464 to be more precise

anonymous · Answer

Oh I see! So, wait how did (you) they know to use the inverse function? Like when is it appropriate to use the inverse?

mtwizzle420 · Answer

Can you help me with some geometry pretty please

mtwizzle420 · Answer

I need help with SohCahToa