Factor the common factor out of the expression 1) -6n+2
\[2) 15n ^{3}+9\] \[3) 7x ^{5}+63x ^{4}+21x ^{2}\] \[4)70a ^{6}+100a ^{3}-40a ^{2}-50a\] \[5) 21n ^{4}+3n ^{3}+27n ^{2}-30n\]
ok so 1 you factor out the two 2 you need to use sum of cubes 5 you need to group with parenthesis
then maybe use synthetic for 3 and 4?
1. -6n+2 = - 3*2n +2 what numers are common ?
7x^{5} + 63x^{4} + 21x^{2} has three terms. Each term has a multiple of 7 in it. Can you factor out 7 from each term? Write your result in the form 7( ).
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@jhonyy9 the common number is 2 right?
yes right for the first one
So two's the answer or is there another step?
for the first one yes is 2 sure because than you see it there are just 2 the common number in every two terms - yes ?
Right
ok. good luck bye bye
@mathmale the common number would be 7
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