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OpenStudy (adrianna.gongora):
\[\frac{ 2 }{ 2+5i }\]
OpenStudy (greatlife44):
Hm.. you want to rationalize this?
OpenStudy (mathmusician):
you want to move the 5i to the other side of the fraction
OpenStudy (adrianna.gongora):
It says to simplify the given expression.
OpenStudy (mathmusician):
you do that by multiplying both the numerator and the denominator by 2+5i
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OpenStudy (greatlife44):
I'm wondering if this could be a step
@mathmusician
\[\frac{ 2 }{ 2+5i }*(\frac{ 2-5i }{ 2-5i })\]
OpenStudy (greatlife44):
\[i = \sqrt{-1}\]
OpenStudy (greatlife44):
\[i^{2} = (\sqrt{-1})^{2} = -1\]
OpenStudy (adrianna.gongora):
Here this is the question and the answer choices.
OpenStudy (mathmusician):
Yes that is a a step @greatlife44
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OpenStudy (adrianna.gongora):
It's the last question I have and I'm just stuck on it
OpenStudy (greatlife44):
I'm wondering if this could be a step
@mathmusician
\[\frac{ 2 }{ 2+5i }*(\frac{ 2-5i }{ 2-5i })\]
\[(2+5i)(2-5i) = (4-25i^{2})\]
remember if we apply the fact that i^{-2} = -1 we can simplify our denominator.
\[i^{2} = -1\]
4-25(-1)
4-(-25) = 29
\[\frac{ 4-10i }{ 29 }\]
OpenStudy (adrianna.gongora):
How did you get the 4-10i ?
OpenStudy (adrianna.gongora):
Never mind I see it
OpenStudy (adrianna.gongora):
Thank you both so much I didn't even know what to do. I was completely stuck on it.
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OpenStudy (greatlife44):
@Adrianna.Gongora
the idea is to get i out of the denominator.