Help?
\[\frac{ 2 }{ 2+5i }\]
Hm.. you want to rationalize this?
you want to move the 5i to the other side of the fraction
It says to simplify the given expression.
you do that by multiplying both the numerator and the denominator by 2+5i
I'm wondering if this could be a step @mathmusician \[\frac{ 2 }{ 2+5i }*(\frac{ 2-5i }{ 2-5i })\]
\[i = \sqrt{-1}\]
\[i^{2} = (\sqrt{-1})^{2} = -1\]
Here this is the question and the answer choices.
Yes that is a a step @greatlife44
It's the last question I have and I'm just stuck on it
I'm wondering if this could be a step @mathmusician \[\frac{ 2 }{ 2+5i }*(\frac{ 2-5i }{ 2-5i })\] \[(2+5i)(2-5i) = (4-25i^{2})\] remember if we apply the fact that i^{-2} = -1 we can simplify our denominator. \[i^{2} = -1\] 4-25(-1) 4-(-25) = 29 \[\frac{ 4-10i }{ 29 }\]
How did you get the 4-10i ?
Never mind I see it
Thank you both so much I didn't even know what to do. I was completely stuck on it.
@Adrianna.Gongora the idea is to get i out of the denominator.
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