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Mathematics 18 Online
OpenStudy (adrianna.gongora):

Help?

OpenStudy (adrianna.gongora):

\[\frac{ 2 }{ 2+5i }\]

OpenStudy (greatlife44):

Hm.. you want to rationalize this?

OpenStudy (mathmusician):

you want to move the 5i to the other side of the fraction

OpenStudy (adrianna.gongora):

It says to simplify the given expression.

OpenStudy (mathmusician):

you do that by multiplying both the numerator and the denominator by 2+5i

OpenStudy (greatlife44):

I'm wondering if this could be a step @mathmusician \[\frac{ 2 }{ 2+5i }*(\frac{ 2-5i }{ 2-5i })\]

OpenStudy (greatlife44):

\[i = \sqrt{-1}\]

OpenStudy (greatlife44):

\[i^{2} = (\sqrt{-1})^{2} = -1\]

OpenStudy (adrianna.gongora):

Here this is the question and the answer choices.

OpenStudy (mathmusician):

Yes that is a a step @greatlife44

OpenStudy (adrianna.gongora):

It's the last question I have and I'm just stuck on it

OpenStudy (greatlife44):

I'm wondering if this could be a step @mathmusician \[\frac{ 2 }{ 2+5i }*(\frac{ 2-5i }{ 2-5i })\] \[(2+5i)(2-5i) = (4-25i^{2})\] remember if we apply the fact that i^{-2} = -1 we can simplify our denominator. \[i^{2} = -1\] 4-25(-1) 4-(-25) = 29 \[\frac{ 4-10i }{ 29 }\]

OpenStudy (adrianna.gongora):

How did you get the 4-10i ?

OpenStudy (adrianna.gongora):

Never mind I see it

OpenStudy (adrianna.gongora):

Thank you both so much I didn't even know what to do. I was completely stuck on it.

OpenStudy (greatlife44):

@Adrianna.Gongora the idea is to get i out of the denominator.

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