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what is (f+g)(x)? f(x) = x2 – 4 and g(x) = x – 2
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pretty sure it's based on this identity \[(f+g)(x) = f(x)+g(x)\]
so is it x^2-2+x?
Hey, what do you think we do first?
x^2+6+x thats the answer i got but idk if its right
I think you would add the functions
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Well the directions say, "What is F + G" So (x) Is the number we have to plug in. But all we do is plug in G for F so we have x(x-2)^2-4
So we follow, PEMDAS What would we do first?
Sorry not x(x-2) its x-2^2-4
so i got the first try right?
but doesnt 2 negatives make a possitive?
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\[(f+g)(x) \ne (f\circ g)(x)\]
@JAGR2713 doesn't that mean f(g(x)) ?
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