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Mathematics 19 Online
OpenStudy (anonymous):

what is (f+g)(x)? f(x) = x2 – 4 and g(x) = x – 2

OpenStudy (greatlife44):

pretty sure it's based on this identity \[(f+g)(x) = f(x)+g(x)\]

OpenStudy (anonymous):

so is it x^2-2+x?

jagr2713 (jagr2713):

Hey, what do you think we do first?

OpenStudy (anonymous):

x^2+6+x thats the answer i got but idk if its right

OpenStudy (marcelie):

I think you would add the functions

jagr2713 (jagr2713):

Well the directions say, "What is F + G" So (x) Is the number we have to plug in. But all we do is plug in G for F so we have x(x-2)^2-4

jagr2713 (jagr2713):

So we follow, PEMDAS What would we do first?

jagr2713 (jagr2713):

Sorry not x(x-2) its x-2^2-4

OpenStudy (anonymous):

so i got the first try right?

OpenStudy (anonymous):

but doesnt 2 negatives make a possitive?

OpenStudy (anonymous):

\[(f+g)(x) \ne (f\circ g)(x)\]

OpenStudy (greatlife44):

@JAGR2713 doesn't that mean f(g(x)) ?

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