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can someone explain how to graph: y=1/2*cos(3ø+m/3)
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think of the parent function \(\ y=\cos \theta \)
what is the period of cos ?
The period is pi
2pi i mean sorry
so knowing that we want to find the period of \(y=\frac{1}{2} \cos (3\theta+\frac{m}{3}) \)
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we set \(3\theta +\frac{m}{3}=2\pi\) solve for theta
you get \(\theta =\frac{2\pi}{3}-\frac{m}{9}\) this our period
so the period is where the graph repeats it self
what you need to think of is the graph of cos theta how you can translate it to that graph
1/2 is the amplitude period I did it horizontal shift solve theta /3 +m/3=0 this is good enough to tell you about the graph
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thank you so much, made so much sense
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