Question

Solve the system of linear equations below.
2x + 3y = 2
x + 6y = 4

Answer 1

/| 2*x+3*y-2 = 0| x+6*y-4 = 0
We try to solve the equation: 2*x+3*y-2 = 0
2*x+3*y-2 = 0 // - 2*x-2
3*y = -(2*x-2) // : 3
y = (-(2*x-2))/3
y = (2-(2*x))/3
We insert the solution into one of the initial equations of our system of equations
We get a system of equations:
/| 6*((2-(2*x))/3)+x-4 = 0| y = (2-(2*x))/3
(6*(2-2*x))/3+x-4 = 0
4-3*x-4 = 0
-3*x = 0
-3*x = 0 // : -3
x = 0
We insert the solution into one of the initial equations of our system of equations
For y = (2-(2*x))/3:
y = (2-(0*2))/3
y = (0+2)/3
y = 2/3
We get a system of equations:
/| y = 2/3| x = 0

Answer 2

do you have any question about that?

Answer 3

you can also use elimination method

Answer 4

if you have any question you can massage me back.

Answer 5

bye

Answer 6

okay

Answer 7

hola como esestas

Answer 8

x = 0, y = 2

3




x = 2, y = - 2

3




x = 4

3 , y = 2

9



x = 4, y = -2

Answer 9

@joojoe those the answer you can choose from