Question

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Answer 1

How would I factor this 8y^2 + 6y + 1

Answer 2

why not try that quadratic equation method i told you yesterday?

Answer 3

I don't remember what you told me yesturday..there was so much random things happening to you..you said many things /;

Answer 4

For a general quadratic equation
\[\large\rm ax^2+bx+c=0 \]
you can find the factors by
\[\large\rm (x-\frac{-b\pm\sqrt{b^2-4ac}}{2a}) \]

Answer 5

Now does that make any sense or you need a demonstration?

Answer 6

I think you should demostrate..btw i have to factor trinomial /:

Answer 7

Okay well can you recognize the values of a and b and c?

Answer 8

I think a and b are the factors

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Answer 9

No okay dont jump to that
if a quadratic equation is
\[\large\rm ay^2+by+c \] and you are given equation
\[\large\rm 8y^2+6y+1 \]
So what are the values of a, b and c

Answer 10

@AloneS Did you get it?