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How would I factor this 8y^2 + 6y + 1
why not try that quadratic equation method i told you yesterday?
I don't remember what you told me yesturday..there was so much random things happening to you..you said many things /;
For a general quadratic equation \[\large\rm ax^2+bx+c=0 \] you can find the factors by \[\large\rm (x-\frac{-b\pm\sqrt{b^2-4ac}}{2a}) \]
Now does that make any sense or you need a demonstration?
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I think you should demostrate..btw i have to factor trinomial /:
Okay well can you recognize the values of a and b and c?
No okay dont jump to that if a quadratic equation is \[\large\rm ay^2+by+c \] and you are given equation \[\large\rm 8y^2+6y+1 \] So what are the values of a, b and c
@AloneS Did you get it?
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