Question

Can someone help with this?

Answer 1

hmm are you doing trig?

Answer 2

have you heard of soh cah toa?

Answer 3

SOH: Sin Opposite/Hypotenuse
CAH: Cosine Adjacent/Hypotenuse
TOA: Tangent Opposite/Adjacent

Answer 4

SOH CAH TOA is da bomb!
\(sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\)

you can mixit with milk, goes with waffles, you can wear it on your hat, or use it as screensaver

Answer 5

XD @jdoe0001 could you help me?

Answer 6

It's a geometry class & they're giving me things idk, or haven't learned about...

Answer 7

So I just need to practice until I get it you know?

Answer 8

well... hmm have you covered the SOH CAH TOA? the trigonometric identities of \(sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\)?

Answer 9

no

Answer 10

@jdoe0001

Answer 11

hmmm then.. you'd want to do that about now, check your book on it, and what it means :)

since you'd need it to get angle B

Answer 12

http://www.mathsisfun.com/algebra/sohcahtoa.html

Answer 13

I don't have a book its all online, can you help me? @jdoe0001

Answer 14

@jim_thompson5910 @Directrix

Answer 15

how far did you get after @jdoe0001 helped you out?

Answer 16

no where;(

Answer 17

so the equations that @jdoe0001 set up and mentioned are completely unfamiliar to you?

Answer 18

yes @jim_thompson5910

Answer 19

would you agree that the size of the angles of the triangle are somehow connected and related to the sides of the triangle?

Answer 20

let's say we had this triangle

Answer 21

what happens to the angle where x is located when the side where y is located gets longer

Answer 22

Yes @jim_thompson5910