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Algebra II question, see attachment!
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goes down 10, put that number aside
then it goes up \[10\times \frac{4}{5}\] and down \[10\times \frac{4}{5}\] for a total of \[20\times \frac{4}{5}\]
next one will be \[20\times \left(\frac{4}{5}\right)^2\] and so on
wait i'm confused, i did 20 * (4/5)^2 and got 12.8
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@CloverRacer You have to do it again. 12.8 * (4/5)^2 and so on.. total of 5 bounces
I think...
i'm not getting a correct answer
like the fifth bounce isn't any of the options
then do to the fourth bounce?hm..
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still doesn't work
i got it, it was \[57 (29/125)\]
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